Module 4 Problem Set Quiz

Module 4 Problem Set

• Question 1

  Write electron (subshell) configurations for the following atoms:

  ₁₉K                    

  ₃₅Br                      

  Correct Answer

  

   

• Question 2

  Write orbital diagrams for the following atoms:

  ₁₅P                        ₂₈Ni         

  Correct Answer

  ORBITAL DIAGRAMS

  ₁₅P     =     1s² 2s² 2p⁶ 3s² 3p³

   ↑↓   ↑↓   ↑↓ ↑↓ ↑↓   ↑↓   ↑ ↑ ↑  

  1s   2s        2p       3s     3p

   ₂₈Ni     =     1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁸

   ↑↓   ↑↓   ↑↓ ↑↓ ↑↓   ↑↓   ↑↓ ↑↓ ↑↓   ↑↓   ↑↓ ↑↓ ↑↓ ↑ ↑

  1s   2s        2p       3s        3p       4s             3d

• Question 3

  Write the values for the four quantum numbers for a 4d⁸ electron.

  Correct Answer

  Orbital diagram for the 4d⁸ orbital

  ↑↓↑↓↑↓↑↑

  A 4d⁸ electron is in the 4th shell so n = 4.  Its "d" orbital has 2 nodal planes so l = 2.  The electron is in the 3rd of the orbitals of the d subshell so m_l = 0.  And since this is the 2nd electron to occupy this "d" orbital, m_s = -1/2.  In summary, the values for the four quantum numbers for the 4d⁸ electron are: n = 4, l = 2, m_l = 0 and m_s = -1/2.

• Question 4

  Write the values for the four quantum numbers for the last electron to fill ₂₈Ni.

  Correct Answer

  Electron configuration for Ni

  

  Orbital Diagram for 3d orbital is 

  ↑↓↑↓↑↓↑↑

  The last electron to fill ₂₈Ni is a 3d⁸ electron which is in the 3rd shell so n = 3.  Its "d" orbital has 2 nodal planes so l = 2.  The electron is in the 3rd of the orbitals of the d subshell so m_l = 0.  And since this is the 2nd electron to occupy this "d" orbital, m_s = -1/2.  In summary, the values for the four quantum numbers for the 3d⁸ electron are: n = 3, l = 2, m_l = 0 and m_s = -1/2.

• Question 5

  Choose the atom that matches the identified atomic property and explain your answer based on the periodic trend and its position within a group or period in the periodic table.

  Highest Ionization Energy: Li, Be, B

  Correct Answer

  B has the highest ionization energy since it is farthest to right of these elements and ionization energy increases as you go from left to right in a period.

• Question 6

  Choose the atom that matches the identified atomic property and explain your answer based on the periodic trend and its position within a group or period in the periodic table.

  Lowest Electronegativity: Li, Be, B

  Correct Answer

  Li has the lowest electronegativity since it is farthest to left of these elements and electronegativity increases as you go from left to right in a period.

• Question 7

  Choose the atom that matches the identified atomic property and explain your answer based on the periodic trend and its position within a group or period in the periodic table.

  Largest Atomic Size: Li, Be, B

  Correct Answer

  Li has the largest atomic size since it is farthest to left of these elements and atomic size decreases as you go from left to right in a period.

• Question 8

  Create an orbital diagram and Lewis dot structure for ₁₆S.

  Correct Answer

  Electron configuration of S

  

  Orbital diagram for S

  ↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↑

  1s 2s   2p    3s  3p

  Lewis structure

  From the orbital diagram, there are 2 unpaired electrons in the 3p orbital. Thus, the Lewis structure of S is: